Functions Grade 11 - Textbook

(f(x)=x^2+1), (g(x)=2x-3) Find ((f\circ g)(x) = f(g(x)) = (2x-3)^2 + 1 = 4x^2 -12x + 10) 3. Transformations of Functions Given (y = a,f(k(x-d)) + c):

Key: (b>0, b\neq 1) If (b>1) → growth; if (0<b<1) → decay. functions grade 11 textbook

However, I put together a structured “paper” / study guide that mirrors the key topics, learning objectives, and practice problems you would find in a typical Grade 11 Functions textbook (Ontario curriculum MCR3U). (f(x)=x^2+1), (g(x)=2x-3) Find ((f\circ g)(x) = f(g(x)) =

(y = a\sin(k(x-d)) + c) Amplitude = (|a|), Period = (360^\circ/|k|) (or (2\pi/|k|) rad), Phase shift = (d), Vertical shift = (c) (y = a\sin(k(x-d)) + c) Amplitude = (|a|),

(y = 3\cos(2x - \pi) + 1) Rewrite: (y = 3\cos(2(x - \pi/2)) + 1) Amplitude 3, Period (360/2=180^\circ) ((\pi) rad), Phase shift (\pi/2) right, Vertical shift 1 up. 8. Sequences & Series Arithmetic sequence: (t_n = a + (n-1)d) Sum of (n) terms: (S_n = \fracn2(2a + (n-1)d))

A population starts at 500, doubles every 4 hours. Model: (P(t) = 500 \cdot 2^t/4) where (t) in hours.

Start with (f(x)=x^2). Apply: vertical compression by (1/2), shift right 3, shift up 4. [ y = \frac12 (x-3)^2 + 4 ] 4. Inverse Functions Switch (x) and (y) in (y=f(x)), then solve for (y). Inverse exists if (f) is one‑to‑one (passes horizontal line test).